ninja windows: suppress 'Creating library...' output

pylib/gyp/win_tool.py

 #!/usr/bin/env python
 
 # Copyright (c) 2012 Google Inc. All rights reserved.
 # Use of this source code is governed by a BSD-style license that can be
 # found in the LICENSE file.
 
 """Utility functions for Windows builds.
 
 These functions are executed via gyp-win-tool when using the ninja generator.
 """
 
 import os
 import shutil
+import subprocess
 import sys
 
 
 def main(args):
   executor = WinTool()
   exit_code = executor.Dispatch(args)
   if exit_code is not None:
     sys.exit(exit_code)
 
 
@@ skipping 18 matching lines @@
     if os.path.exists(dest):
       if os.path.isdir(dest):
         shutil.rmtree(dest)
       else:
         os.unlink(dest)
     if os.path.isdir(source):
       shutil.copytree(source, dest)
     else:
       shutil.copy2(source, dest)
 
+  def ExecLinkWrapper(self, *args):
+    """Filter diagnostic output from link that looks like:
+    '   Creating library ui.dll.lib and object ui.dll.exp'
+    This happens when there are exports from the dll or exe.
+    """
+    popen = subprocess.Popen(args,
+                             stdout=subprocess.PIPE,
+                             stderr=subprocess.STDOUT)
+    out, _ = popen.communicate()
+    for line in out.splitlines():

[Nico, 2012/04/03 23:13:12]

You can just iterate over popen.stdout, which will yield the output in line form
i think. (and when you're done reading, popen.returncode is ready.) at least
that works on posix.

+      if not line.startswith('   Creating library '):
+        sys.stdout.write(line)
+    return popen.returncode
 
 if __name__ == '__main__':
   sys.exit(main(sys.argv[1:]))