Do not call showErrorAndExit "out" of order

dart/pkg/unittest/test_controller.js

Index: dart/pkg/unittest/test_controller.js
diff --git a/dart/pkg/unittest/test_controller.js b/dart/pkg/unittest/test_controller.js
index 3698b3e95588b79e7b0c289939c5829ff1ba6a40..0f797d0e70ab7b426ac1cf238347b26ce86e1df4 100644
--- a/dart/pkg/unittest/test_controller.js
+++ b/dart/pkg/unittest/test_controller.js
@@ -112,10 +112,6 @@ function dartMainRunner(main) {
   try {
     main();
   } catch (e) {
-    showErrorAndExit(String(e));
-    // Calling showErrorAndExit will not call testRunner.notifyDone()
-    // at this point. This is because of the async nature of this framework.
-    // testRunner.startedDartTest is not true yet. So post a message.
     window.postMessage('unittest-suite-fail', '*');
     return; // Posting 'dart-main-done' signals success.
   }